AB=5 cm, BC=4 cm and AC =6 cm. State with reason whether it is possible to draw ∆ABC or not.
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In a ∆,
sum of two sides > third side.
Here, AB = 5
BC = 4
AC = 6
So, in a ∆,
AB + BC > AC
=> 5 + 4 > 6
=> 9 > 6
AB + AC > BC
=> 5 + 6 > 4
=> 11 > 4
AC + BC > AB
=> 6 + 4 > 5
=> 10 > 5
All conditions are applicable here. Also, in a ∆, difference of two sides < third side
=> AB - BC < AC
=> 5 - 4 < 6
=> 1 < 6
AC - AB < BC
=> 6 - 5 < 4
=> 1 < 4
AC - BC < AB
=> 6 - 4 < 5
=> 2 < 5
All conditions are applicable, hence the triangle is possible.
sum of two sides > third side.
Here, AB = 5
BC = 4
AC = 6
So, in a ∆,
AB + BC > AC
=> 5 + 4 > 6
=> 9 > 6
AB + AC > BC
=> 5 + 6 > 4
=> 11 > 4
AC + BC > AB
=> 6 + 4 > 5
=> 10 > 5
All conditions are applicable here. Also, in a ∆, difference of two sides < third side
=> AB - BC < AC
=> 5 - 4 < 6
=> 1 < 6
AC - AB < BC
=> 6 - 5 < 4
=> 1 < 4
AC - BC < AB
=> 6 - 4 < 5
=> 2 < 5
All conditions are applicable, hence the triangle is possible.
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1
Answer:
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