Question

AB = 6 cm, ∠BAQ = 500

. Draw a circle passing through A and B so

that AQ is the tangent to the circle ​

Answer 1

Step-by-step explanation:

BAQ=30

∘

Since AB is the bisector of ∠CAQ

∠CAB=∠BAQ=30

∘

∠CAQ=∠CAB+∠BAQ=60

∘

We can also see that: ∠PAC+∠CAQ=180

∘

So,∠PAC=120

∘

Since AD bisects ∠PAC

So,∠PAD=∠DAC=

2

∠PAC

=60

∘

So,∠DAB=90

∘

And we know that only diameter subtends an angle of 90

∘

on the circle

Hence part (I) is proved

Now we see that ∠CAB & ∠ACBare equal because they share a same side in front on them