Question

Ab=6 ,dc=5,bc=4,ab=3 , ka displacement and distance​

Answer 1

it is blur i cant see it proparly

Answer 2

Answer:

Given, AB=8cm;BC=4cm

Perpendicular distance between AB and BC is DL=3cm

The area of the parallelogram =base×height

                                                  =AB×DL

                                                  =8×3=24cm  

2

 

Area of the parallelogram =base×height

                                           =AD×BM

                                      24=4×height

                             Height=6cm

So the perpendicular distance between AD and BC is 6cm

Explanation: