Math, asked by navyameht, 7 months ago

AB= 65, BC= 90, AC= 5 which type of triangle is this

Answers

Answered by Queenhu826
0

Answer:

PR+QR = 25 (given) and PR=25-QR

52 + QR2= PR2 (pythagorean theorem)

Then substitute PR to get this equation =  52 + QR2 = (25-QR)2

Solve for QR

52 + QR2 = 625 - 50QR +QR2                  .........(QR2 cancels out)

52 = 625 - 50 QR

-600 = -50 QR

QR= 12

Solve for PR using original equation.

PR= 13

Now draw the triangle on your paper for help solving the next step...

Sin = opposite/ hypootenuse  Sin(P)= 12/13

Cos= Adjacent/ hypotenuse Cos(P) = 5/13

Tan= opposite/ adjacent  Tan(P) = 12/5

Answered by neelb274
0

Answer:

It can't form a triangle.

Step-by-step explanation:

According to the triangle inequality,

the sum of any two sides of a triangle should always be greater than the thrid side.

But, here, if we use the inequality,

AB + AC > BC

=> 65 + 5 > 90

=> 70>90

but 70 < 90.

Hence, the assumption contradicts the inequality.

So, we can conclude that these three sides cannot form a triangle.

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