AB= 65, BC= 90, AC= 5 which type of triangle is this
Answers
Answer:
PR+QR = 25 (given) and PR=25-QR
52 + QR2= PR2 (pythagorean theorem)
Then substitute PR to get this equation = 52 + QR2 = (25-QR)2
Solve for QR
52 + QR2 = 625 - 50QR +QR2 .........(QR2 cancels out)
52 = 625 - 50 QR
-600 = -50 QR
QR= 12
Solve for PR using original equation.
PR= 13
Now draw the triangle on your paper for help solving the next step...
Sin = opposite/ hypootenuse Sin(P)= 12/13
Cos= Adjacent/ hypotenuse Cos(P) = 5/13
Tan= opposite/ adjacent Tan(P) = 12/5
Answer:
It can't form a triangle.
Step-by-step explanation:
According to the triangle inequality,
the sum of any two sides of a triangle should always be greater than the thrid side.
But, here, if we use the inequality,
AB + AC > BC
=> 65 + 5 > 90
=> 70>90
but 70 < 90.
Hence, the assumption contradicts the inequality.
So, we can conclude that these three sides cannot form a triangle.