Question

ab(a^2+b^2) and evaluate as ,a =2 and b =1/2​

Answer 1

Given :

• Evaluate :

$\red \bigstar \bf \: ab( {a}^{2} + {b}^{2} )$

To Find :

• The remaining values of this equation =?

Solution :

Given values :

$\bullet \bf \: a = 2$

$\\ \bullet \bf \: b = \frac{1}{2}$

Substituting the values a and b in given equation

$\implies \bf \: ab( {a}^{2} + {b}^{2} )$

$\\ \implies \sf 2 \times \frac{1}{2} \bigg( {(2)}^{2} + { \bigg( \frac{1}{2} \bigg) }^{2} \bigg)$

$\\ \implies \sf \: 1 \bigg(4 + \frac{1}{4} \bigg)$

$\implies \boxed{ \bf{ \frac{17}{4} }}$

The remaining values of this equation is

$\implies \boxed { \tt{ \frac{17}{4} }}$

Answer 2

Answer:

$ab(a {}^{2} + b {}^{2}) \\ \\ a = 2 \: \: \:, b = \frac{1}{2} \\ \\ ab(a {}^{2} + b {}^{2}) \\ = 2 \times \frac{1}{2} [{2}^{2} + (\frac{1}{2} ){}^{2} ] \\ </p><p>= [4 + \frac{1}{4} ] \</p><p>=[ \: \frac{16 + 1}{4} ] \\</p><p>= [ \frac{17}{4} ]$

hope you got it

thanks