ab-a-b+1 = ?
Please write the correct answer taking common
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3(x − 2) is the factored form of 3x − 6, and (x − 1)( x + 6) is the factored from ... We divide each term by and see what is left. ... Example. Factor 6a2b − 8ab + 10ab2. Solution.
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Step-by-step explanation:
ab-a-b+1 = ?
=> ab - a - b = -1
=> - ( -ab + a + b) = -1
=> a + b -ab = 1
By Taking 'a' as common
=> a ( b - b) = 1
=> b-b = a
=> a = 0
So now 'b' =
a + b -ab = 1
=> 0 + b -0b = 1
=> b = 1
Hence, a = 0 and b = 1 .
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