√ab=√a√b for positive real numbers a and b , tha following identities
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the following identities hold for positive real numbers a and b
Given,
( √a + √b ) ( √a - √b) = a - b
The identities are:
( a + b )² = a² + 2ab + b²
( a - b )² = a² - 2ab + b²
( a + b ) ( a - b ) = a×a - a×b + b×a - b×b = a² - b²
Similarly,
( √a + √b ) ( √a - √b )
= √a × √a - √a × √b + √b × √a - √b × √b
= a - b
Hence proved.
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Answer:
above answer is correct
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