Question

AB a tangent drawn from a point A to a circle with centre O and BOC is a diameter of the circle such that
AOC = 110". Find OAB.

Answer 1

Answer:

Step-by-step explanation:

☺☺ HERE IS YOUR ANSWER ☺......

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In ∆ BOA,

Angle OBA = 90 . ..........(OB perpendicular tangent PB)

angle BOA + angle COA = 180. ........( linear angles)

angle BOA = 180 - 120

angle BOA = 60

Angle BOA + Angle ABO + Angle BAO = 180

60 + 90 + Angle BAO = 180

Angle BAO = 180 - 150

Angle BAO = 30.

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HOPE IT HELPS.....

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