ab,A2 , B2 are diatomic molecules if the bond enthalpies of a2,ab and b2 in the ratio 1:1:0.5 the enthalpy of formation of a bi from a 2 + b 2 is - 100 kj mol -1 what is the bond enthalpy of A2
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Answer:
Explanation:
A2+B2=2AB
1/2A2+1/2B2=AB
Deborah=-100kj
-100=(X/4+X/2)-x
X=400KJ/Mol
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