ab(a2+b2-c2) +bc( a2+b2-c2) -ca(a2+b2-c2)
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Hey!
ab(a² + b²- c²) + bc(a² + b²- c²) - ca(a² + b²- c²)
Taking (a² + b²- c²) common
(a² + b²- c²)(ab + bc - ca)
Hope it help
Answered by
2
Answer:
(ab+bc-ca)(a²+b²-c²)
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