Math, asked by saurabhspal13, 1 day ago

ab (a²+b²-c²)-bc(c²-a²-b²)+ca(a²+b²-c²) factories by taking out common factor.​

Answers

Answered by abhishekjain08
0

Answer:

ab(a2+b2−c2)−bc(c2−a2−b2)+ca(a2+b2−c2)

=ab(a2+b2−c2)+bc(−c2+a2+b2)+ca(a2+b2−c2)

=(a2+b2−c2)[ab+bc+ca]

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