AB=AC & DB=DC,find the ratio of angle ABD : angle ACD
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hello mates
answer is
in ΔABC
AB=AC
∴∠ABC=∠ACB(angles opposite to equal sides of a triangle are equal)......1
in ΔDBC,
DB=DC,
∴∠DBC=∠DCB(angles opposite to equal sides of a triangle are equal)......2
subtract 2 from 1
∠ABC-∠DBC=∠ACB-∠DCB(equals subtracted from equals gives equal)
=∠ABD=∠ACD
divide both the sides by ∠ACD
⇒∠ABD/∠ACD=1
∴∠ABD:∠ACD=1:1
hope it help you....
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