AB=AC AND ANGLE ABC = 68 DEGREE.WHAT IS ANGLE BPC?
pahiroy1221:
u mean angle BAC right ?
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AB = AC
Therefore ABC is an isosceles triangle .
∠ABC = 68°
Therefore ∠ACB = 68°
now,
by angle sum property of a triangle :
∠ABC + ∠BAC + ∠ACB = 180°
68° + 68° + ∠BAC = 180°
136° +∠BAC = 180°
∠BAC = 180°-136°
∠BAC = 44°
I hope it helps...........
Therefore ABC is an isosceles triangle .
∠ABC = 68°
Therefore ∠ACB = 68°
now,
by angle sum property of a triangle :
∠ABC + ∠BAC + ∠ACB = 180°
68° + 68° + ∠BAC = 180°
136° +∠BAC = 180°
∠BAC = 180°-136°
∠BAC = 44°
I hope it helps...........
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