AB=AC and AP =AQ. can you say that BP =CQ? which axiom are using for this?
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Answered by
90
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Given that AP=AQ
Since , AB=AC, AP-AB =AQ-AC
From fourth axiom,If equals are subtracted from equals, then the remainders are equal.
ie, BP = CQ
HOPE , IT HELPS ... ✌
___________________________
Given that AP=AQ
Since , AB=AC, AP-AB =AQ-AC
From fourth axiom,If equals are subtracted from equals, then the remainders are equal.
ie, BP = CQ
HOPE , IT HELPS ... ✌
Answered by
6
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