AB=AC,D is a mid point of BC,SHOW,AngleABC=AngleACD,Also show AD is a bisector of angle A
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angle ABC =angle ACD ...because angle opposite to equal sides in a triangle are equal..
now, in triangle ABD & triangle ACD,
angle B= angle C
AB=AC ...given
BD=DC ...mid point at D
so, ABD congurent to triangle ACD ...by SAS criterion
therefore.,angle BAD=CAD...i.e. D is the bisector of angleA ...by CPCT
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