Question

AB= AC IN ∆ABC. IF ANGLE A=50° ,FIND ANGLE B AND C​

Answer 1

Hi friend

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Your answer

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In ∆ ABC , We have,

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AB = AC

so, ∆ABC is an isosceles triangle.

Then,

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Angle B = Angle C

Angle A = 50° (given)

Angle B = Angle C = (180° - 50°)/2

= 130°/2

= 65°

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Answer 2

since AB=AC, so B=C

A+B+C=180

50+2C=180

2C=130

C=65

THEREFORE

B=65 ; C=65