AB=AC , Suppose D is the mid point of BC.Prove that AD is perpendicular to BC
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Between ∆ABD and ∆ADC
AB=AC
BD=CD
AD is common side
∆ABD and ∆ADC are congruent (S-S-S)
So, angle ADB = angle ADC.
Since, <ADB + <ADC = 180°
=> <ADB = 90°=<ADC
hence AD perpendicular to BC
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