AB and AC are equal chord of a circle . BC is produced to P so that CP = CA. If PA cuts the circle at Q, prove that BQ bisects angle ABC
Answers
Answer:
Given: AB and CD are two equal chord of the circle.
Prove: Center O lies on the bisector of
the ZBAC.
Construction: Join BC. Let the bisector on
ZBAC intersect BC in P.
Proof:
In A APB and A APC
AB-AC
(Given)
ZBAP-ZCAP
(Given)
AP=AP
(common)
A APB=AAPC
SAS test
-BP-CP and ZAPB-ZAPC
CPCT
ZAPB+ZAPC=180° (Linear pair)
22APB-180°. (ZAPB-ZAPC)
ZAPB=90°
AP is perpendicular bisector of chord
BC.
Hence, AP passes through the center of the circle.
MARK AS BRAINLIST
Answer:
Hanji Aditya bro good evening
kkrh
Given a line AB with Point C outside it. Mark point D on the line AB. Join CD With D as center, and any radius, draw an arc intersecting AB at E, and CD at F. With C as center, and same radius as before, draw an arc intersecting CD at G. Open a compass to length EF Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H. Draw a line m passing through C and H. Thus m is
Explanation:
please mark brainlist