English, asked by aditya541677, 10 hours ago

AB and AC are equal chord of a circle . BC is produced to P so that CP = CA. If PA cuts the circle at Q, prove that BQ bisects angle ABC​

Answers

Answered by iamsusantaroy
9

Answer:

Given: AB and CD are two equal chord of the circle.

Prove: Center O lies on the bisector of

the ZBAC.

Construction: Join BC. Let the bisector on

ZBAC intersect BC in P.

Proof:

In A APB and A APC

AB-AC

(Given)

ZBAP-ZCAP

(Given)

AP=AP

(common)

A APB=AAPC

SAS test

-BP-CP and ZAPB-ZAPC

CPCT

ZAPB+ZAPC=180° (Linear pair)

22APB-180°. (ZAPB-ZAPC)

ZAPB=90°

AP is perpendicular bisector of chord

BC.

Hence, AP passes through the center of the circle.

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Answered by itzHappyBandiXx
2

Answer:

Hanji Aditya bro good evening

kkrh

Given a line AB with Point C outside it. Mark point D on the line AB. Join CD With D as center, and any radius, draw an arc intersecting AB at E, and CD at F. With C as center, and same radius as before, draw an arc intersecting CD at G. Open a compass to length EF Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H. Draw a line m passing through C and H. Thus m is

Explanation:

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