Question

AB and AC are tangents in the circle with centre O. Tangent PQ touches the circle at point as shown in figure B R a (i) Can you say AB = AC? (ii) Show that (a) AB = AP + PR (b) AC = AQ + QR (c) AB + AC = AP + PQ+ AQ 50- Find ROP and OPS​

Answer 1

Answer:

Solution

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Given, a circle inscribed in △ABC, such that the circle touches the sides of the triangle.

Tangents drawn to a circle from an external point are equal.

∴AP=AR=7cm

CQ=CR=5cm

Now, BP=AB−AP=10−7=3cm

∴BP=BQ=3cm

∴BC=BQ+QC=3+5=8cm

∴ the length of BC is 8cm