Question

AB and AC are the two chords of a circle whose radius is r. If p and q are the distance of chord AB and CD, from the centre respectively and if AB = 2AC then proove that 4q2 = p2 + 3r2 .

Answer 1

Answer:

4q^2 = p^2 + 3 r^2

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

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