Question

AB and AC are two chords of a circle which are mutually perpendicular to each other. AB = 5 cm and AC = 12 cm. The length of radius of the circle is?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

IF AB=5CM AND AC=12 AND THEY ARE PERPENDICULAR TO EACH OTHER THEN THE DIAMETER IS THE HYPOTENOUS OF THIS CHORD THEN BC = DIAMETER OF THE CIRCLE THEN BC = AB

${ab }^{2} + {ac }^{2} = {bc}^{2}$

then bc 13 cm