Math, asked by Pracgsrasitca, 1 year ago

AB and AC are two chords of the circle of radius r. If AB = 2AC and the perpendiculars drawn from the centre on these chords from the centre on these chords are of lengths 'a ' and 'b ', prove that 4b 2 = a 2 + 3r 2 .

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Answered by BrainlyYoda

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