AB and AC are two equal chords of a circle prove that the bisector of angle BAC passes through the centre of the circle
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It is given that AB=AC Now join BC
→∆ABC is Isoceles
BC is now a chord
There is a property that in a isosceles triangle Angle bisector bisects opposite side and is perpendicular to it
→ Bisector of angle BAC bisects BC
Theorem says perpendicular from center bisects the chord
→ Angle bisector of BAC passes through center O
→∆ABC is Isoceles
BC is now a chord
There is a property that in a isosceles triangle Angle bisector bisects opposite side and is perpendicular to it
→ Bisector of angle BAC bisects BC
Theorem says perpendicular from center bisects the chord
→ Angle bisector of BAC passes through center O
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