Question

AB and AC are two identical chords of a circle of radius 5 cm. The circle center ABC is located outside the triangle, Find the length of BC chord being AB = AC = 6 cm.​

Answer 1

Answer:

Given - AB and AC are two equal words of a circle, therefore the centre of the circle lies on the bisector of BAC.

OA is the bisector of BAC.

Again, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the angle.

P divides BC in the ratio = 6 : 6 = 1 : 1.

P is mid-point of BC.

OP BC.

In ABP, by Pythagoras theorem,