Question

AB and AC are two tangents to a circle having centre O. If angle BOC = (3x – 8°) and angle BAC = (2x + 3°), find x.​

Answer 1

answer = X.= 37°

EXPLAINATION=

Angle A =2x +3

Angle B =90°(angle made by radius on the

tangent = 90°)

Angle C =90° ⬆️

Angle BOC= 3x-8

we know that sum of all angles of quad. =360°

Therefore---

90+90+2x+3+3x-8=360°

183-8+5x=360°

175+5x=360°

5x=360-175

5x=185

x=185÷5

x=37

So,angle A = 2 × 37 + 3=77°

angle BOC= 3 × 37 - 8 =103°

Answer 2

Answer:

hope the answer helps you....