AB and AC are two uniform rods of length 12m and 8 m respectively. if angle BAC =60° .find the distance from A of the C.G. of the two rods
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Correct option is
A
19/14 m on the side of heavier rod
C
1
and C
2
be the center of two rod.
Now X be the distance of com from side of heavier rod.
X=
m
1
+m
2
m
1
x
1
+m
2
x
2
=
ϱ
1
×5+ϱ
2
×3
(ϱ
1
)×5+2.5×ϱ
2
×3×6.5
=
21
15×2.5+6×6.6
=
21
76.5
=
7
25.5
=
14
51
fromA
Center of mass will be 5−x from left of point B.
=
14
19
left from B heavier end of joining.
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