Question

AB and CD are 2 parallel chords of a circle such that AB = 10 cm and CD =24 cm if the chords on the oppositte sides of the centre and the distance between them is 17 cm find radius of the circle​

Answer 1

Answer:

Step-by-step explanation:

since op perpendicular to ab and oq perpendicular to cd nd ab parallel to cd

poq is a st. line

ab=10cm,cd=24cm nd pq is 17cm

ap=bp=half ab = 5cm and cq=dq=half cd =12cm

if oq=x cm ,then op= (17-x)cm

join oa nd oc

oa=oc=r(radius)

now in right angled triangle oap,

oa square=op square+ap square

=r square=(17-x)square+ 5square_ist equation

in right angled triangle ocq,

oc square=oq square+cq square

=r square=x square+12square_2nd equation

frm ist nd 2nd equations ,we get :

on solving we get x=5

r square=x square+12 square

r square=5 square+12 square

r square= 25+144

r = 13cm

radius of the circle is 13cm