Question

ab and CD are common tangents of two circles of unequal radius prove that AB= CD​

Answer 1

Answer:

Just draw another tangent AD.

Now consider tangents AD and DC.

Since lengths of tangents from an external point to a circle is equal.

AD = CD ------------[1]

Similarly, AD = AB -------------[2] ( with the same reason ) .

Now from [1] and [2]

AB = CD

Hence proved.

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