AB and CD are respectively the smallest and the largest side of a quadrilateral ABCD. prove that:
∠A is greater than ∠c
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DC>AB(GIVEN)
DC>AD(CD IS THE LONGEST)
ANGLE A > ANGLE C(ANGLE OPPOSITE TO LONGER SIDE IS GREATER)
DC>BC(CD IS THE LONGEST ANGLE)
HENCE PROVED
DC>AD(CD IS THE LONGEST)
ANGLE A > ANGLE C(ANGLE OPPOSITE TO LONGER SIDE IS GREATER)
DC>BC(CD IS THE LONGEST ANGLE)
HENCE PROVED
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