Question

AB and CD are the diameter of a circle if the coordinate of the points are A (2 ,3)     B ( 8,7).     C (1,4)  then coordinate of point D is

A) (-9.6)

B). (6,-9)

C). ( 9,6)

D) (5,5)​

Answer 1

Answer:

Correct option is

A

(−6,7)

Let the coordinates of the one end of a diameter AB of a circle are A(2,3) and B(x,y).

Let the coordinates of the center of the circle C(−2,5).

As center is the midpoint of the diameter AB so the coordinates of center is

C(

2

2+x

,

2

3+y

)

Now equating the coordinates of center we get

2

2+x

=−2

⇒2+x=−4

⇒x=−4−2

x=−6

2

3+y

=5

⇒3+y=10

⇒y=10−3

⇒y=7

∴Coordinates of B=(−6,7).