AB and CD are the smallest and largest sides of a quadrilateral ABCD. Out of <B and <D decide which is greater.
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In the fig. ABCD is a quadrilateral with AB as the smallest side, and CD as the largest side.
We join the diagonal BD.
We label the angles as shown in the figure as θ1 , θ2, θ3, θ4 as shown in figure.
Now in ΔABD,
AB<AD
⟹θ2<θ1→(1)
Similarly in ΔBCD,
BC<CD
⟹θ4<θ3→(2)
Adding (1)and(2),
θ2+θ4<θ1+θ3
which is nothing but,
∠D<∠B
Thus ∠(B) will be greater
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