Question

AB and CD are two chords of a circle which are 3 cm away from the center .of AB =8 then find the length of CD​

Answer 1

Answer:

we know that when two chords of a circle intersect either inside or out side then the area of the rectangle formed by the segments of one chord is equal to the area of the rectangle formed by the segments of the other.

So in this let CD = x cm

Then AE × BE = CE × DE

ie. 14×3 = (x+3.5)×3.5

So x+3.5 = 14×3/3.5 => x+3.5 = 4×3

So x= 12 - 3.5 = 8.5. so CD = 8.5 cm