AB and CD are two chords of a circle which intersect at a point O inside the circle. It is given that, AB = 10 cm, CO= 1.5 cm and DO = 12.5 cm. What is the ratio between the larger and smaller among AO and BO?
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Answer:
CM x DM=144 cm.
Step-by-step explanation:
This question is related to intersecting chords theorem .Intersecting chords are two straight lines segments whose both end points lie on a circle and both are intersecting each other in a circle. The theorem states that:
When in a circle two chords intersect each other the product of their segment would be equal.
Now ,
OP = PQ =radius=13 cm.
OQ = diameter=13*2= 26 cm
AB=CD=chords
M=the point at which the chords intersect.
PM= 5 cm
0M = OP - PM= 13-5= 8 cm
QM=PM + PQ = 13+5=18 cm
Now according to the intersecting theorem we have:
CM x DM = OM X QM= 8*18 =144 cm
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