Ab and cd are two chords of a circle which intersect each other externally at p. If bp = 3 cm, cp=6 cm and cd=2 cm, then find ab
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Step-by-step explanation:
By rule of similarity of triangle (AAA ) Tri(PCB) similar to Tri (PAD)
(because angle PCB is equal to angle PAD and angle P is common in both )
hence PB/PD =PC/PA
3/8=6/PB +AB
3/8=6/AB+3 by CM
3AB+ 9 =48
3AB=39
AB=13
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