Question

AB and CD are two chords of the circle with centre O . OP and OQ are perpendicular on chords AB and CD .If angle POQ is 150° ,these find angle APQ
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Answer 1

Answer:

see below

Step-by-step explanation:

Since AB=CD (equal chords) so, their distance from centre must le equal

So, OP=OQ

Now, In △POQ

(1) ∠OPQ=∠OQP

(2) ∠OPQ+∠OQP+∠POQ=180  

0

 

⇒2∠OPQ+150  

0

=180  

0

 

⇒∠OPQ=15  

0

 

Also, ∵P is midpoint of AB

OP⊥AB⇒∠APO=90  

0

 

Now, ∠APQ=∠APO−∠OPQ=90  

0

−15  

0

=75  

0