AB and CD are two equal chords of the given circle with centre O. Prove that the suburbs angles of the chords at the centre are equal.
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Step-by-step explanation:
In∆OAB & ∆OCD:
OA=OC(RADIUS)
OB=OD(RADIUS)
AB=CD(GIVEN)
HENCE,∆OAB =~ ∆OCD(SSS-CRITERIA)
HENCE angleAOB=angleCOF proved✓✓
Answered by
1
Answer:
According to circle theorem:- equal chord make equal angle at centrre.
or
<BOA=<COD
This can be prove by taking triangle BOA and COD
Step-by-step explanation:
in triangle BOA and COD
AB = CD (given)
AO = OD (Radii of circle)
BO = OC (Radii of circle)
So,
Triangle BOA congruent triangle COD
SO <BOA = <COD. (CPCT)
I hope it will help you.
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