Question

AB and CD are two parallel chord of length 8 cm and 6 cm respectively . If they are 1 cm apart and lie on the same side of the center of the circle, find the radious of the circle​

Answer 1

Answer:

Step-by-step explanation:

If we draw a line perpendicular to the chords and another line at the end of the chords

we will get two right angled triangle

One side will be the radius(endpoint of chord)

And the perpendicular will divide the chords in 2 equal halves

If the length of one perpendicular is x another one will be x+1 as they have a distance of 1cm

the base of the 2 triangles will be 8/2 and 6/2 respectively and hypotensue will be the radius

So by applying pythagorus theorem we get

4²+x²=r²(for chord 8cm)

3²+(x+1)²=r²(for 6cm chord)

4²-3²+x²-(x+1)1=0

16-9+x²-x²-2x-1=0

7-2x-1=0

2x=6

x=3

Putting x=3 in eqn 1 we get

4²+3²=r²

r²=16+9

r²=25

r=5 cm

Answer 2

Answer:

5 cm is ur answer

Step-by-step explanation:

by Pythagorean theorem