AB and CD are two parallel chords and O is the centre. If AB = 24 cm,
CD=18cm and radius by= 15 cm. Find the distance between the chords,
if both the chords are:
(i) on the opposite sides of the centre,
(ii) on the same side of the centre.
Answers
Answered by
2
Answer:
In the figure, chords AB∥CD
O is the centre of the circle
Radius of the Circle = 15 cm
Length of AB = 24 cm and CD = 18 cm
Join OA and OC
AM = MB = 24/2 = 12 cm
Similarly ON⊥CD
CN = ND = 18/2 = 9 cm
In right △AMO
OA
2
=OM
2
+AM
2
OM
2
=OA
2
−AM
2
OM
2
=15
2
+12
2
=225−144
OM=
81
=9
Similarly in right △CNO
OC
2
=CN
2
+ON
2
(15)
2
=(9)
2
+ON
2
225=81+ON
2
ON
2
=225−81
ON=12cm
Now MN=OM+ON=9+12=21cm
Similar questions