Question

AB and CD are two parallel chords of a circle length, 10 cm and 4 cm respectively. If the chords lies on the same side of the centre and distance between them is 3cm​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

ANSWER

According to the problem

OA+OC=radii of corcle

Therefore

OE⊥AB,OC⊥CD

Since

AE=EB=5Cm

CF=FD=2Cm

let OE=XCm

In ΔOAE,

OA

2

=AE

2

+OE

2

Implies that

OA

2

=5

2

+x

2

(1)

InΔOCE,

OC

2

=2

2

+(x+3)

2

(2)

Since

5

2

+x

2

=2

2

+(x+3)

2

Implies that

25+x

2

=4+x

2

+6x+9

Implies that

6x=25−13

6x=12

x=

6

12

x=2cm