AB and CD are two parallel chords of a circle of lengths 10 cm and 4 cm respectively
de lie on the same side of the centre and the distance between them is 3cm
If the chords lie on the same side of centre
find the diameter of the circle.
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length of the chords=10,4
dist.b/w Chords=di-d2=3
r2=(C/2)^2+d1 ^2
r2=2^2+d1^2
r2=5^2+d2^2
Subtract->
O=4-25 + di^2-d2^2
o =-21-di^2-d2^2
di^2-d2^2 = 21
(di+d2)(di-d2)=21
(di+d2)x3=21
di+d2=7
di-d2=3
Add->
2 di=10
di=5
di+d2=7
d2=2
di=5. d2=2
To find r, radius
di=5,C/2 = 4/2=2
r =vdi^2+(c/2)^2
=v5^2+2^2 =v 25 +4=v 29=5.4cm
diameter = 10.8cm
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