Question

AB and CD are two parallel chords of a circle of radius 13 cm lying on the opposite side of the centre. if AB=10 cm and CD=24 cm find the distance between the two chords​

Answer 1

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17 will be the answer....

AB=10 CM

SO, half of AB=QC=5 CM

radius=CO=13 cm

so by applying pythagoras theorem,

OQ=$\sqrt{13^2-5^2}$

OQ=$\sqrt{169-25}$

  OQ=12 cm

CD=24 CM

SO, half of CD=AP=12 CM

radius=AO=13 cm

so by applying pythagoras theorem,

OP=$\sqrt{13^2-12^2}$

OP=$\sqrt{169-144}$

  OP=5 cm

ANSWER=(5+12)cm=17cm