Question

AB and CD are two parallel chords of a circle whose whose centre is O

and radius is 20cm .If AB =24cm and CD =32cm. Find distance between

AB and CD if they lie i) on opposite side of centre.

ii) on the same side of centre.​

Answer 1

Answer:

Given

Δ ANO is a right angle triangle,

∴ using pythogoras theorem,

OA  

2

=ON  

2

+AN  

2

 

13  

2

=ON  

2

+12  

2

 

ON  

2

=13  

2

−12  

2

=169−144

ON  

2

=25

⇒ON  

2

=5cm

Similarly for ΔOCM

OC  

2

=OM  

2

+CM  

2

 

13  

2

=OM  

2

+5  

2

 

OM  

2

=13  

2

−5  

2

 

OM  

2

=169−25

OM=  

144

​  

 

=12cm

∴ Distance between chorts

=OM+ON

=12+5

=17cm.

Thus the distance between the two chords is 17cm.

Step-by-step explanation: