Math, asked by pranav20041027, 10 months ago

AB and CD are two parallel chords of a circle with centre O and radius 5cm such that AB=8cm and CD=6cm,if OP perpendicular to AB and OQ perpendicular to CD determine the length PQ.​

Answers

Answered by surabhijatte667
1

Answer:

7 cm

length of op = 3

length of oq=4

= 3+4 = 7 cm

Answered by sarthakghotekar721
2

Answer:

Step-by-step explanation:

Answer:

The length of PQ is 7 cm.

Step-by-step explanation:

Given information: The radius of the circle is 5 cm. AB=8 cm and CD = 6 cm. OP⊥AB, OQ⊥CD.

From the below figure it is noticed that triangle AOP and COQ are right angled triangle.

Perpendicular from the center always a chord bisector.

Use Pythagoras theorem in triangle AOP,

The length of OP is 3 cm.

Use Pythagoras theorem in triangle COQ,

The length of OP is 3 cm.

The length of PQ is

Therefore the length of PQ is 7cm

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