AB and CD are two parallel chords of a circle with centre O and radius 5cm such that AB=8cm and CD=6cm,if OP perpendicular to AB and OQ perpendicular to CD determine the length PQ.
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Answered by
1
Answer:
7 cm
length of op = 3
length of oq=4
= 3+4 = 7 cm
Answered by
2
Answer:
Step-by-step explanation:
Answer:
The length of PQ is 7 cm.
Step-by-step explanation:
Given information: The radius of the circle is 5 cm. AB=8 cm and CD = 6 cm. OP⊥AB, OQ⊥CD.
From the below figure it is noticed that triangle AOP and COQ are right angled triangle.
Perpendicular from the center always a chord bisector.
Use Pythagoras theorem in triangle AOP,
The length of OP is 3 cm.
Use Pythagoras theorem in triangle COQ,
The length of OP is 3 cm.
The length of PQ is
Therefore the length of PQ is 7cm
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