AB and CD are two parallel chords on the
same side of the circle such that AB = 6 cm.
CD = 8cm the small enunt is as a distance
ey 4cm from the circt centre. At what
distance from the centre is the other
chord.
Answers
Step-by-step explanation:
Answer: 3 cm.
Step-by-step explanation: Let O be the centre of the circle. AB and CD are two parallel chords on the same side of the centre, where AB=6 cm and CD=8 cm. Also, OB and OD are the radius of the circle, OE=4 cm. To find OF.
Since OE⊥AB, so AE=EB=3 cm. Similarly, BF=FD=4 cm.
Now, from right angled triangle OEB, we have
So, OB=OD=5 cm.
Again, from right angled triangle OFD, we have
Thus, the distance of the other chord CD from the centre is 3 cm.
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