Question

AB and CD are two parallel lines of a circle whose diameter is AC. prove AB=CD

Answer 1

here AC is perpendicular to AB and CD .so AB=CD

Answer 2

Given: AB and CD are two parallel lines of the circle such that ABCD and AC is the diameter of the circle.

TPT: AB = CD

proof:

in the triangles CBA and ADC,

∠CBA = ∠ADC = 90 [angles in the semi circle]

∠BAC = ∠ACD [alternate interior angles]

AC is common.

therefore by AAS congruency, triangles are congruent.

thus AB = CD cpct

hope its helps you.