Question

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will be
A. 55°
B. 70°
C. 110°
D. 130°

Answer 1

∠CFQ = 110°

option C is correct

•∠LEB =35°

•∠LEF =35° as EL is the bisector of ∠FEB

•∠FEB = 70°

•As AB || CD

•∠FEB = ∠EFC (Alternate interior

angles)

•∠EFC = 70°

•Also ∠EFC + ∠CFQ = 180° ( Linear

pair)

•70° +∠CFQ = 180°

•∠CFQ = 180 -70

•∠CFQ = 110°