AB and CD are two parallel organisms in a P concentric circle. Center P is between AB and CD. If AB = 48 cm, CD = 40 cm and the radius of the circle is 25 cm, find the distance between AB and CD.
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Answer: Since the perpendicular from the center of a circle to a chord bisect the chord.
AB=2LB
LB=5cm
CD=2MD
MD=12cm
In angle OLB,
[OB]²=[OL]²+[LB]²
[r]²=x²+[5]²
r²=x²+25
In angle OMD
[OD]²=[OM]²+[MD]²
r²=[17-x]²+[12]²
r²=[17-x]²+144
From equation 1 and 2 we get
x²+25=[17-x]²+144
x²+25=289+x²-34x+144
x²25=x²-34x+433
Cut xx
x=12
From equation r²=x²+25
r²=[12]²+25
144+25
r²=169
r=13cm
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