Question

AB and CD are two parlled sides of a cyclisc quardrilateral ABCD such that AB=12cm,CD=16 and the raduis of the cricle is 10CM find the shortest distannce between the two sides AB and CB

Answer 1

Answer:

According to the question,

∵△OMD and △ONB are right angled triangle

And, OD = OB = R

In △OMD, from tirplets

5, 12, 13

OM = 5 cm, OD = 13 cm, MD = 12 cm.

Again, In △ONB, from triplets

5, 12, 13

OB = 13 cm, ON = 12 cm

∵ OB = OD = 13 cm

Radius = 13 cm.