AB and CD bisect each other at K. Prove that AC =BC.
PLEASE solve this with process.
Attachments:
Riishu:
sorry its AC = BD
Answers
Answered by
1
AC AND BC CAN NEVER BE EQUAL IT CAN BE AC = BD
yes
Answered by
3
In triangles AKC and BKD,
AK = KB [K is the midpoint of AB]
CK = KD [K is the midpoint of CD]
angle AKC = angle DKB [vertically opposite angles]
therefore,
triangle AKC congruent to triangle BKD by SAS axiom
=> AC = BD [corresponding sides]
AK = KB [K is the midpoint of AB]
CK = KD [K is the midpoint of CD]
angle AKC = angle DKB [vertically opposite angles]
therefore,
triangle AKC congruent to triangle BKD by SAS axiom
=> AC = BD [corresponding sides]
Similar questions