Question

AB and CD bisect each other at K. Prove that AC =BD BUT easy step

Answer 1

solution⤵️

Given,
AB and CD bisect each other at K
=> AK=BK and CK=DK

To prove: AC=BD

proof: AC and BD are joined
Now,
in ∆ACK and ∆BDK,
AK=BK (given)
CK=DK (given)
<AKC=<BKD (Vertically opposite angles)
therefore,∆ACK=~∆BDK (SAS)
=> AC=BD

HENCE proved